Geometry · Trapezoids · Angle bisectors · Cyclic quadrilaterals · Pencils of lines

Problem 4, 2024

← Prev · 48 / 198 · Next →

CityProof

Let \(X\) be the midpoint of the base \(AB\) of a trapezoid \(ABCD\) (\(AB \parallel CD\)). Prove that if

\[ \angle ADX = \angle BCX, \]

then the bisectors of the angles \(\angle ADX\), \(\angle DXC\) and \(\angle XCB\) belong to a single pencil of lines, that is, either all three pass through one point or all three are parallel.

A B X D C
Trapezoid \(ABCD\) with \(AB \parallel CD\); \(X\) is the midpoint of \(AB\), and the marked angles \(\angle ADX\) and \(\angle BCX\) are equal.

Sign in to check answers, open hints, read the full solution, and track your progress. Statements are always free.

Serbian Municipal Competition 2024, high school grade I, category A, problem 4. Organized by the Mathematical Society of Serbia (DMS). Source