Algebra · Proportions · Ratios · Fractions · Algebraic manipulation
Problem 2, 1996
← Prev · 1 / 57 · Next →Let \(a\), \(b\), \(c\), \(d\) be positive real numbers such that
\[ \frac{5a+b}{5c+d} = \frac{6a+b}{6c+d} \qquad \text{and} \qquad \frac{7a+b}{7c+d} = 8 . \]
Determine the value of \(\dfrac{9a+b}{9c+d}\).
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Serbian Republic Competition (Republicko takmicenje) 1996, high school grade I, problem 2. Organized by the Mathematical Society of Serbia (DMS). Source